A light bulb consuming 60 watts with 0.9 amperes of current has what resistance?

To find the resistance of the light bulb, you can use Ohm's Law and the formula for electrical power. The formula for power (P) in terms of current (I) and resistance (R) is:

[ P = I^2 \cdot R ]

From this formula, we can rearrange it to solve for resistance:

[ R = \frac{P}{I^2} ]

In this scenario, the power of the light bulb is given as 60 watts, and the current is 0.9 amperes. To find the resistance, first calculate the square of the current:

[ I^2 = (0.9)^2 = 0.81 \text{ amperes}^2 ]

Now, substitute the values into the rearranged formula:

[ R = \frac{60 \text{ watts}}{0.81 \text{ amperes}^2} ]

Calculating this gives:

[ R = \frac{60}{0.81} \approx 74.07 \text{ ohms} ]

This is how the correct answer of approximately 74.07 ohms is derived. Using this formula accurately calculates resistance based on power and current, which