In a DC series circuit, how does the voltage drop across resistors relate to their resistance values?

In a DC series circuit, the voltage drop across each resistor is directly proportional to its resistance value, as described by Ohm's Law, which states that ( V = I \times R ). In this context, the voltage (V) across a resistor is the product of the current (I) flowing through the circuit and the resistance (R) of that resistor.

In a series circuit, the same current flows through all components, which means that the voltage drop across each resistor varies depending on its resistance. Specifically, a higher resistance in the series will result in a larger voltage drop because the product of the constant current and the larger resistance yields a larger voltage. Therefore, the relationship holds true that higher resistance results in a higher voltage drop across that resistor.

This concept is fundamental in understanding how voltage is distributed in a series circuit, ultimately leading to the conclusion that as resistance increases, the corresponding voltage drop also increases, confirming the correctness of the answer regarding the behavior of voltage in relation to resistance in a DC series circuit.