What is ER2 in a DC series circuit with R1 = 150 ohms, R2 = 150 ohms, R3 = 550 ohms, and IT = 0.2 amperes?

In a DC series circuit, the total voltage across the circuit can be calculated using Ohm's Law, which states that Voltage (V) equals Current (I) multiplied by Resistance (R). In this case, we can determine the total resistance (RT) of the circuit by summing up the individual resistances: R1, R2, and R3.

The total resistance is: RT = R1 + R2 + R3

RT = 150Ω + 150Ω + 550Ω = 850Ω.

Given that the total current (IT) flowing through the circuit is 0.2 amperes, we can now calculate the total voltage (VT) across the entire circuit using Ohm's Law: VT = IT × RT VT = 0.2A × 850Ω = 170 volts.

Next, we need to find the voltage drop across R2, which has a resistance of 150 ohms. The voltage drop (ER2) across a resistor in a series circuit can also be determined using Ohm’s Law, specifically for that resistor: ER2 = IT × R2 ER2 = 0.2A × 150Ω = 30 volts.

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